what is the strength of the electric field at the position indicated by the dot in (figure 1)?

what is the strength of the electric field at the position indicated by the dot in (figure 1)? Specifies the direction as an angle from the horizon. θ = ⁰. Answer: Charges are equidistant and both positive, so they repel with the same magnitude. Drawing a force cancels out the y component of the final field. Only the x component is present. And since they are the same, the resulting electric field will be twice the x component of the charge’s electric field. E=kq/r^2r= 5 x root2 = 7.07 cm or .0707 m (45-45 -90 right triangle properties) E=(9 x 10^9)(1 x 10^-9)/(. 0707 )^2= 1800.